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5v^2-2v-51=0
a = 5; b = -2; c = -51;
Δ = b2-4ac
Δ = -22-4·5·(-51)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-32}{2*5}=\frac{-30}{10} =-3 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+32}{2*5}=\frac{34}{10} =3+2/5 $
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